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Assume liquefied petroleum gas (LPG) is ...

Assume liquefied petroleum gas (LPG) is a 50-50 (by mole) mixture of n-pentane and n-butnane.Calculate the calorific value (in `KJ//"mol"`) of gas available form a newly filled cylinder.
Give your answer divide by 100.
`{:( ,n-"butane",C_4H_10 n-"pentane" C_6H_12),("Vapour pressure",1800 "Torr",600 "Toor"),("Calorific value ",2800 kJ//"mol",3600 kJ//"mol"):}`

Text Solution

Verified by Experts

The correct Answer is:
30 KJ/mol, increase
30 kJ/mol , increase
First of all we find mole fractions in liquid mixture, let mixture is 100 mole
So moles of pentane=50
moles of Butane=50
So, `X_("pentane")=0.5 " " X_("Butane")=0.5`
`P_T=600xx0.5+1800xx0.5=1200`
`Y_("pentane")=300/1200=1/4 " " Y_("Butane")=900/1200=3/4`
Calorific value `=3600xx1/4+2800xx3/4`=3000 kJ/mol
During use
`Y_("pentane") " " "calorific value" uarr`
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