The variation of concentration of 'A' with time in two experiments starting with two different initial concentration of 'A' is given by the following graph.The reaction is represented by `A(aq)toB(aq)` what is rate of reaction `(M//min)` when conc. of A in aqueous solution was 1.8 M:

Options

A. 0.072 M `"min"^(-1)`
B. 0.1296 M `"min"^(-1)`
C. 0.036 M `"min"^(-1)`
D. 1 M `"min"^(-1)`

Answer

A

Explanation

`r_1=0.3/5 M min^(-1) implies r_2=0.2/5`
`r_1/r_2=[A_1/A_2]^m implies 0.3/0.2=(1.5/1)^mimplies m=1 : " " 0.3/5=k(1.5),k=1/25`
`r=1/25xx1.8=0.072 Mmin^(-1)`