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An queous solution of an acid is so wea...

An queous solution of an acid is so weak that it can be assumed to be prectically unionised, boiled at `100.4^(@)C` 25 ml of this solution was neurtrased by 38.5 ml of 1 N solution of NaOH. Calculate basicity of the acid if `k_(b)(H_(2)O)=0.52" k mol"^(-1)" kg"`. Assume molality is equal to malarity.

A

10 mL

B

40 mL

C

100 mL

D

160 mL

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The correct Answer is:
D

NA
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An aqueous solution of an acid is so weak that it can be assumed to be practically unionised, boiled at 100.4^(circ)C . 25 mL of this solution was neutralised by 38.5 mL of 1N solution of NaOH . Calculate basicity of the acid if K_(b) for water is 0.52 K mol^(-1) kg . Assume molality equal to molarity.

0.84 g of a acid (mol wt. 150) was dissolved in water and the volume was made up to 100 ml. 25 ml of this solution required 28 ml of (N/10) NaOH solution for neutralisation. The equivalent weight and basicity of the acid

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A 0.1 molal solution of an acid is 4.5% ionized. Calculate freezing point. (molecular weight of the acid is 300 ). K_(f)="1.86 K mol"^(-1)"kg".

A 5 per cent aqueous solution by mass of a non-volatile solute boils at 100.15^(@)C . Calculate the molar mass of the solute. K_(b)=0.52 K kg "mol"^(-1) .

A 0.025 m solution of mono basic acid had a freezing point of 0.06^(@)C . Calculate K_(a) for the acid K_(f) for H_(2)O=1.86^(@) "molality"^(-1) .

2.0 molal aqueous solution of an electrolyte X_(2) Y_(3) is 75% ionised. The boiling point of the solution a 1 atm is ( K_(b(H_(2)O)) = 0.52K kg mol^(-1) )

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