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A mixutre solution of KOH and Na2CO3 req...

A mixutre solution of KOH and `Na_2CO_3` requires 15 " mL of " `(N)/(20)` HCl when titrated with phenolphthalein as indicator.But the same amoound of the solutions when titrated with methyl orange as indicator requires 25 " mL of " the same acid. Calculate the amount of KOH present in the solution.

A

0.014 g

B

0.14 g

C

0.028 g

D

1.4 g

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(a Mili eq.)(KOH)+underset(b Mili eq.)(Na_2CO_3)`
`a+b/2=15xx1/20`
2a+b=1.5 ..(i) (in presence of phenolphthalein)
`a+b=25xx1/20=1.25`…(ii)(in presence of Methyl orange)
by solving (i) & (ii) a = 0.25 Mili eq.
mass of KOH=`0.25/1000xx56=0.014` gm
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