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If 100 mL "of" 1 M H(2) SO(4) solution i...

If `100 mL "of" 1 M H_(2) SO_(4)` solution is mixed with `100 mL` of 98% `(W//W)` of `H_(2)SO_(4)` solution `(d = 0.1 g mL^(-1))`, then

A

concentration of solution remains same

B

volume of solution become 200 ml

C

mass of `H_2SO_4` in the solution is 98 gm

D

mass of `H_2SO_4` in the solution is 19.6 gm

Text Solution

Verified by Experts

The correct Answer is:
A,B,D
(A)Molarity of second solution is `=(10xxdxxx)/M=1M`
(B)Volume=100+100=200 ml
( D)Mass of `H_2SO_4=(200xx1)/1000xx98=19.6` gm
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