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Assertion: In the redox reaction 8H^(+)(...

Assertion: In the redox reaction `8H^(+)(aq)+4NO_(3)^(-)+6Cl^(-)+Sn(s) rarr SnCl_(6)^(2-)+4NO_(2)+4H_(2)O`. the reducing agent is `Sn(s)`.
Reason In balacing half-reaction, `S_(2)O_(3)^(2-) rarr S(s)`, the number of electrons added on the left is `4`.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

Text Solution

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To solve the question, we need to analyze the assertion and reason provided in the context of the redox reaction: **Assertion:** In the redox reaction \(8H^+(aq) + 4NO_3^{-} + 6Cl^{-} + Sn(s) \rightarrow SnCl_6^{2-} + 4NO_2 + 4H_2O\), the reducing agent is \(Sn(s)\). **Reason:** In balancing the half-reaction, \(S_2O_3^{2-} \rightarrow S(s)\), the number of electrons added on the left is 4. ### Step-by-Step Solution: 1. **Identify the Oxidation States:** - In the reaction, we need to determine the oxidation states of the elements involved. - For \(Sn(s)\), the oxidation state is 0. - In \(SnCl_6^{2-}\), the oxidation state of \(Sn\) can be calculated as follows: - Each \(Cl\) has an oxidation state of -1, so for 6 \(Cl\), the total is -6. - Therefore, \(Sn\) must have an oxidation state of +4 to balance the -6 from \(Cl\) to give a total charge of -2. 2. **Determine the Role of \(Sn\):** - Since \(Sn\) goes from an oxidation state of 0 to +4, it is losing electrons and is therefore oxidized. - The species that gets oxidized is the reducing agent. Hence, \(Sn(s)\) is indeed the reducing agent in this reaction. 3. **Analyze the Reason:** - The reason discusses the half-reaction involving \(S_2O_3^{2-}\) and its reduction to \(S(s)\). - In this half-reaction, \(S\) in \(S_2O_3^{2-}\) has an oxidation state of +2. To reduce it to elemental sulfur (0 oxidation state), 2 electrons are required for each sulfur atom. - Since there are 2 sulfur atoms in \(S_2O_3^{2-}\), a total of 4 electrons are needed for the complete reduction. 4. **Conclusion:** - The assertion is correct because \(Sn(s)\) is the reducing agent. - The reason is also correct in stating that 4 electrons are needed, but it does not explain why \(Sn(s)\) is the reducing agent in the given reaction. ### Final Answer: - **Assertion is correct.** - **Reason is correct but does not explain the assertion.**

To solve the question, we need to analyze the assertion and reason provided in the context of the redox reaction: **Assertion:** In the redox reaction \(8H^+(aq) + 4NO_3^{-} + 6Cl^{-} + Sn(s) \rightarrow SnCl_6^{2-} + 4NO_2 + 4H_2O\), the reducing agent is \(Sn(s)\). **Reason:** In balancing the half-reaction, \(S_2O_3^{2-} \rightarrow S(s)\), the number of electrons added on the left is 4. ### Step-by-Step Solution: ...
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Knowledge Check

  • In the reaction, I_(2)+2S_(2)O_(3)^(2-) rarr 2I^(-)+S_(4)O_(6)^(2-) .

    A
    `I_(2)` is reducing agent.
    B
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    C
    `S_(2)O_(3)^(2-)` is oxidising agent.
    D
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