The electronic configuration of Ag atom is

Explanation

To determine the electronic configuration of a silver (Ag) atom, follow these steps:

### Step-by-Step Solution:

1. **Identify the Atomic Number**:
- The atomic number (Z) of silver (Ag) is 47. This means a neutral silver atom has 47 electrons.

2. **Determine the Electron Configuration Order**:
- Electrons fill orbitals in a specific order based on the Aufbau principle, which states that electrons occupy the lowest energy orbitals first. The order of filling is as follows:
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, etc.

3. **Fill the Orbitals**:
- Start filling the orbitals according to the order:
- 1s² (2 electrons)
- 2s² (2 electrons)
- 2p⁶ (6 electrons)
- 3s² (2 electrons)
- 3p⁶ (6 electrons)
- 4s² (2 electrons)
- 3d¹⁰ (10 electrons)
- 4p⁶ (6 electrons)
- 5s² (2 electrons)
- 4d¹⁰ (10 electrons)
- 5s¹ (1 electron)

4. **Count the Total Electrons**:
- Add the electrons filled in each orbital:
- 2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 1 = 47 electrons.

5. **Write the Electronic Configuration**:
- The electronic configuration of silver (Ag) is:
- Kr (Krypton, the nearest noble gas) 4d¹⁰ 5s¹.

### Final Answer:
The electronic configuration of a silver (Ag) atom is **[Kr] 4d¹⁰ 5s¹**.