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Calculate the mass in grams of 0.19 mole...

Calculate the mass in grams of 0.19 mole of `H_2O`.

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The correct Answer is:
20
`PbO_2+4KItoPbI_2+I_2+2K_2O`
`N_2H_2+2I_2toN_2+4HI`
moles of `N_2` liberated `=11.2/22.4=5xx10^(-2)` mole
mole of `PbO_2` reacted `=10^(-1)` mole
`PbO_2+2H_2OtoPb(OH)_4`
`pb(OH)_4+2NaOHtoNa_2[Pb(OH)_6] or Na_2PbO_2`
mole of NaOH required `=10^(-1)xx2`
`Vxx1/10xx10^3=2xx10^(-1) " " V=2/10^(-3)=2000` ml
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