Statement-1 :When a gas at high pressure expands against vacuum, the magnitude of work done is maximum.
Statement-2 :Work is a path function

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Explanation

To solve the question, we need to analyze both statements provided and determine their validity.

### Step 1: Analyze Statement 1
**Statement 1:** When a gas at high pressure expands against vacuum, the magnitude of work done is maximum.

- In the case of a gas expanding against a vacuum, there is no opposing pressure (P_external = 0).
- The work done (W) during expansion is given by the formula:
\[ W = -P_{\text{external}} \Delta V \]
- Since \(P_{\text{external}}\) is zero in this scenario, the work done is:
\[ W = -0 \times \Delta V = 0 \]
- Therefore, the magnitude of work done is not maximum; it is zero.

**Conclusion for Statement 1:** **False**

### Step 2: Analyze Statement 2
**Statement 2:** Work is a path function.

- A path function is a property that depends on the specific path taken between two states, rather than just the initial and final states.
- Work is indeed a path function because the amount of work done depends on the specific process (path) taken during the transition from one state to another.
- For example, if we consider two different processes between the same initial and final states on a PV diagram, the work done will differ depending on the path taken.

**Conclusion for Statement 2:** **True**

### Final Conclusion
- **Statement 1 is False.**
- **Statement 2 is True.**

Thus, the correct answer is that Statement 1 is false and Statement 2 is true.