The element that has two unpaired electrons in its M2+ ion form is:

Options

A. Mn
B. Cu
C. Zn
D. Ti

Explanation

To determine which element has two unpaired electrons in its M²⁺ ion form, we need to analyze the electronic configurations of the given elements in their M²⁺ state. Here are the steps to solve the problem:

### Step 1: Identify the Elements
We need to analyze the electronic configurations of the following elements in their M²⁺ forms:
1. Manganese (Mn)
2. Copper (Cu)
3. Zinc (Zn)
4. Titanium (Ti)

### Step 2: Determine the Atomic Numbers
- Manganese (Mn) has an atomic number of 25.
- Copper (Cu) has an atomic number of 29.
- Zinc (Zn) has an atomic number of 30.
- Titanium (Ti) has an atomic number of 22.

### Step 3: Write the Electronic Configurations
1. **Mn²⁺**:
- Atomic number 25: Electronic configuration of Mn is [Ar] 4s² 3d⁵.
- For Mn²⁺, we remove 2 electrons from the 4s orbital:
- Mn²⁺: [Ar] 3d⁵ (5 unpaired electrons).

2. **Cu²⁺**:
- Atomic number 29: Electronic configuration of Cu is [Ar] 4s¹ 3d¹⁰.
- For Cu²⁺, we remove 2 electrons (1 from 4s and 1 from 3d):
- Cu²⁺: [Ar] 3d⁹ (1 unpaired electron).

3. **Zn²⁺**:
- Atomic number 30: Electronic configuration of Zn is [Ar] 4s² 3d¹⁰.
- For Zn²⁺, we remove 2 electrons from the 4s orbital:
- Zn²⁺: [Ar] 3d¹⁰ (0 unpaired electrons).

4. **Ti²⁺**:
- Atomic number 22: Electronic configuration of Ti is [Ar] 4s² 3d².
- For Ti²⁺, we remove 2 electrons from the 4s orbital:
- Ti²⁺: [Ar] 3d² (2 unpaired electrons).

### Step 4: Analyze the Unpaired Electrons
- Mn²⁺: 5 unpaired electrons.
- Cu²⁺: 1 unpaired electron.
- Zn²⁺: 0 unpaired electrons.
- Ti²⁺: 2 unpaired electrons.

### Conclusion
The element that has two unpaired electrons in its M²⁺ ion form is **Titanium (Ti)**.

### Final Answer
**Option D: Titanium (Ti)**

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