Home
Class 12
CHEMISTRY
The number of moles of nitrogen present ...

The number of moles of nitrogen present in one litre of air containing 20% nitrogen by volume, under standard condition, is:

A

4.91 x `10^(-3)`

B

8.92 x `10^(-3)`

C

4.91 x `10^(-2)`

D

8.92 x `10^(-2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of moles of nitrogen present in one liter of air containing 20% nitrogen by volume under standard conditions, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Volume of Nitrogen**: - Given that air contains 20% nitrogen by volume, we can calculate the volume of nitrogen in 1 liter of air. - Volume of nitrogen = 20% of 1 liter = \( \frac{20}{100} \times 1 \) liter = 0.20 liters. 2. **Use the Ideal Gas Law**: - Under standard conditions (STP), one mole of an ideal gas occupies 22.4 liters. - We will use this information to find the number of moles of nitrogen in 0.20 liters. 3. **Calculate the Number of Moles**: - The formula to calculate the number of moles (n) is given by: \[ n = \frac{\text{Volume of gas}}{\text{Molar volume at STP}} \] - Substituting the values: \[ n = \frac{0.20 \text{ liters}}{22.4 \text{ liters/mole}} \] 4. **Perform the Calculation**: - Calculate the number of moles: \[ n = \frac{0.20}{22.4} \approx 0.00893 \text{ moles} \] 5. **Express in Scientific Notation**: - The number of moles can be expressed in scientific notation: \[ n \approx 8.93 \times 10^{-3} \text{ moles} \] ### Final Answer: The number of moles of nitrogen present in one liter of air containing 20% nitrogen by volume under standard conditions is approximately \( 8.93 \times 10^{-3} \) moles. ---

To find the number of moles of nitrogen present in one liter of air containing 20% nitrogen by volume under standard conditions, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Volume of Nitrogen**: - Given that air contains 20% nitrogen by volume, we can calculate the volume of nitrogen in 1 liter of air. - Volume of nitrogen = 20% of 1 liter = \( \frac{20}{100} \times 1 \) liter = 0.20 liters. ...
Promotional Banner

Topper's Solved these Questions

  • QUALITATIVE ANALYSIS PART 1

    RESONANCE ENGLISH|Exercise A.L.P|39 Videos
  • SOLID STATE

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (SOLID STATE)|45 Videos

Similar Questions

Explore conceptually related problems

The number of moles of nitrogen present in one litre of air containing 12% nitrogen by volume, under standard condition, is:

The number of moles of nitrogen present in one litre of air containing 15% nitrogen by volume, under standard condition, is:

The number of moles of nitrogen present in one litre of air containing 16% nitrogen by volume, under standard condition, is:

The number of moles of nitrogen present in one litre of air containing 18% nitrogen by volume, under standard condition, is:

The number of moles of nitrogen present in one litre of air containing 19% nitrogen by volume, under standard condition, is:

The number of moles of nitrogen present in one litre of air containing 11% nitrogen by volume, under standard condition, is:

The number of moles of nitrogen present in one litre of air containing 14% nitrogen by volume, under standard condition, is:

The number of moles of nitrogen present in one litre of air containing 17% nitrogen by volume, under standard condition, is:

The number of moles of nitrogen present in one litre of air containing 13% nitrogen by volume, under standard condition, is:

The number of mole of nitrogen in one litre of air containing 10% nitrogen by volume, under standard conditions, is

RESONANCE ENGLISH-RANK BOOSTER-All Questions
  1. The element that has two unpaired electrons in its M2+ ion form is:

    Text Solution

    |

  2. The number of moles of nitrogen present in one litre of air containing...

    Text Solution

    |

  3. The number of moles of nitrogen present in one litre of air containing...

    Text Solution

    |

  4. Mass of one atom of an element is 8.46×10^(−24)g. This is equal to :

    Text Solution

    |

  5. The number of moles of the solute present in 600 ml of 0.05 M solution...

    Text Solution

    |

  6. Internal Energy (E,also denoted by U): Every system having some quan...

    Text Solution

    |

  7. The internal energy of a certain substance is given by the following e...

    Text Solution

    |

  8. The number of moles of the solute present in 500 ml of 0.05 M solution...

    Text Solution

    |

  9. Calculate the mass in grams of 0.15 mole of H2S.

    Text Solution

    |

  10. Calculate the mass in grams of 0.13 mole of H2S.

    Text Solution

    |

  11. The number of moles of the solute present in 500 ml of 0.06M solution ...

    Text Solution

    |

  12. A contributions of both heat (enthalpy) and randomness(entropy) shall ...

    Text Solution

    |

  13. A contribution of both heat (enthalpy) and randomness(entropy) shall b...

    Text Solution

    |

  14. A contributions of both heat (enthalpy) and randomness(entropy) shall ...

    Text Solution

    |

  15. The number of moles of the solute present in 500 ml of 0.04 M solution...

    Text Solution

    |

  16. The number of moles of the solute present in 600 ml of 0.06 M solution...

    Text Solution

    |

  17. Calculate the mass in grams of 0.17 mole of H2S.

    Text Solution

    |

  18. The number of moles of the solute present in 600 ml of 0.5M solution i...

    Text Solution

    |

  19. The number of moles of the solute present in 500 ml of 0.5M solution i...

    Text Solution

    |

  20. The number of moles of the solute present in 500 ml of 0.4M solution i...

    Text Solution

    |