Home
Class 12
CHEMISTRY
Mass of one atom of an element is 8.46×1...

Mass of one atom of an element is 8.46×`10^(−24)`g. This is equal to :

A

5u

B

0.5u

C

1u

D

200 u

Text Solution

AI Generated Solution

The correct Answer is:
To find the mass of one mole of atoms based on the mass of a single atom, we can follow these steps: ### Step 1: Understand the relationship between mass of one atom and mass of one mole The mass of one mole of atoms (also known as molar mass) can be calculated using Avogadro's number, which is approximately \(6.02 \times 10^{23}\) atoms per mole. ### Step 2: Write down the formula The formula to calculate the mass of one mole of atoms is: \[ \text{Mass of one mole} = \text{Number of atoms in one mole} \times \text{Mass of one atom} \] This can be expressed as: \[ \text{Mass of one mole} = N_A \times m \] where \(N_A\) is Avogadro's number and \(m\) is the mass of one atom. ### Step 3: Substitute the values Given: - Mass of one atom, \(m = 8.46 \times 10^{-24} \, \text{g}\) - Avogadro's number, \(N_A = 6.02 \times 10^{23} \, \text{atoms/mole}\) Now, substituting these values into the formula: \[ \text{Mass of one mole} = (6.02 \times 10^{23}) \times (8.46 \times 10^{-24}) \] ### Step 4: Perform the multiplication Calculating the multiplication: \[ \text{Mass of one mole} = 6.02 \times 8.46 \times 10^{23} \times 10^{-24} \] Calculating \(6.02 \times 8.46\): \[ 6.02 \times 8.46 \approx 50.8 \] Now, combining the powers of ten: \[ 10^{23} \times 10^{-24} = 10^{-1} \] Thus, we have: \[ \text{Mass of one mole} \approx 50.8 \times 10^{-1} \, \text{g} = 5.08 \, \text{g} \] ### Step 5: Round the answer Rounding \(5.08 \, \text{g}\) gives us approximately \(5 \, \text{g}\). ### Conclusion Thus, the mass of one mole of the element is approximately \(5 \, \text{g}\) or \(5 \, \text{u}\) (unified atomic mass). ### Final Answer The mass of one atom of the element is equal to \(5 \, \text{g}\). ---

To find the mass of one mole of atoms based on the mass of a single atom, we can follow these steps: ### Step 1: Understand the relationship between mass of one atom and mass of one mole The mass of one mole of atoms (also known as molar mass) can be calculated using Avogadro's number, which is approximately \(6.02 \times 10^{23}\) atoms per mole. ### Step 2: Write down the formula The formula to calculate the mass of one mole of atoms is: \[ ...
Promotional Banner

Topper's Solved these Questions

  • QUALITATIVE ANALYSIS PART 1

    RESONANCE ENGLISH|Exercise A.L.P|39 Videos
  • SOLID STATE

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (SOLID STATE)|45 Videos

Similar Questions

Explore conceptually related problems

Mass of one atom of an element is 6.64× 10^(−24) g. This is equal to :

Mass of one atom of an element is 7.64× 10^(−24) g. This is equal to :

Mass of one atom of an element is 3.64× 10^(−24) g. This is equal to :

Mass of one atom of an element is 8.64× 10^(−23) g. This is equal to :

Mass of one atom of an element is 6.64× 10^(−23) g. This is equal to :

Mass of one atom of an element is 5.64× 10^(−23) g. This is equal to :

Mass of one atom of an element is 4.64× 10^(−23) g. This is equal to :

Mass of one atom of an element is 7.64× 10^(−23) g. This is equal to :

Mass of one atom of an element is 9.64× 10^(−23) g. This is equal to :

Mass of one atom of an element is 4.0X10^-24 g. This is equal to

RESONANCE ENGLISH-RANK BOOSTER-All Questions
  1. The number of moles of nitrogen present in one litre of air containing...

    Text Solution

    |

  2. The number of moles of nitrogen present in one litre of air containing...

    Text Solution

    |

  3. Mass of one atom of an element is 8.46×10^(−24)g. This is equal to :

    Text Solution

    |

  4. The number of moles of the solute present in 600 ml of 0.05 M solution...

    Text Solution

    |

  5. Internal Energy (E,also denoted by U): Every system having some quan...

    Text Solution

    |

  6. The internal energy of a certain substance is given by the following e...

    Text Solution

    |

  7. The number of moles of the solute present in 500 ml of 0.05 M solution...

    Text Solution

    |

  8. Calculate the mass in grams of 0.15 mole of H2S.

    Text Solution

    |

  9. Calculate the mass in grams of 0.13 mole of H2S.

    Text Solution

    |

  10. The number of moles of the solute present in 500 ml of 0.06M solution ...

    Text Solution

    |

  11. A contributions of both heat (enthalpy) and randomness(entropy) shall ...

    Text Solution

    |

  12. A contribution of both heat (enthalpy) and randomness(entropy) shall b...

    Text Solution

    |

  13. A contributions of both heat (enthalpy) and randomness(entropy) shall ...

    Text Solution

    |

  14. The number of moles of the solute present in 500 ml of 0.04 M solution...

    Text Solution

    |

  15. The number of moles of the solute present in 600 ml of 0.06 M solution...

    Text Solution

    |

  16. Calculate the mass in grams of 0.17 mole of H2S.

    Text Solution

    |

  17. The number of moles of the solute present in 600 ml of 0.5M solution i...

    Text Solution

    |

  18. The number of moles of the solute present in 500 ml of 0.5M solution i...

    Text Solution

    |

  19. The number of moles of the solute present in 500 ml of 0.4M solution i...

    Text Solution

    |

  20. The number of moles of the solute present in 600 ml of 0.6M solution i...

    Text Solution

    |