The number of moles of the solute present in 600 ml of 0.05 M solution is:

Options

A. 0
B. 0.01
C. 0.02
D. 0.03

Answer

0

Explanation

`W=-intPdV`
`=-int K/V^n dV=-K/(1-n)[V^(-n+1)]_(V_1)^(V_2)=K/(n-1)[V_2^(1-n)-V_1^(1-n)]`
`=(P_1V_1^n)/(n-1)[V_2^(1-n)-V_1^(1-n)]=(P_1V_1^(n+1-n))/(n-1)[(V2/V_1)^(1-n)-1]`