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In an ionic solid r((+))=1.6A and r((-))...

In an ionic solid `r_((+))=1.6A` and `r_((-))=1.864A`. Use the radius ratio to determine the edge length of the cubic unit cell in `A`.

A

4

B

`2sqrt3`

C

`3sqrt3`

D

`4/sqrt3`

Text Solution

Verified by Experts

The correct Answer is:
A
`r_+/r_(-) = 1.6/1.864=0.858`
So, It is CsCl type of unit cell
So `sqrt3 a=2(r_+ +r_-)`
So `a=(2(1.864+1.6))/sqrt3Å=2xx2Å=4Å`
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