Assertion : An important feature of fluorite structure is that cations being large ib size occupy `FC C` lattice points, the formula unit `AB_(2)` (A cation, B anion)
Reason: There are `6` cations and `12` anions per `FC C` unit cell of the flucrite structure

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Explanation

To solve the question, we need to analyze both the assertion and the reason statements regarding the fluorite structure.

### Step-by-Step Solution:

1. **Understanding the Assertion**:
- The assertion states that an important feature of the fluorite structure is that cations, being larger in size, occupy FCC (Face-Centered Cubic) lattice points, and the formula unit is \( AB_2 \) (where A is the cation and B is the anion).
- In the fluorite structure, the cation (A) is indeed larger and occupies the FCC lattice points.

2. **Understanding the Reason**:
- The reason states that there are 6 cations and 12 anions per FCC unit cell of the fluorite structure.
- To verify this, we need to calculate the number of cations and anions in the FCC unit cell.

3. **Calculating Cations in FCC**:
- In an FCC unit cell, cations are located at the corners and the face centers.
- There are 8 corners (each contributing \( \frac{1}{8} \)) and 6 face centers (each contributing \( \frac{1}{2} \)).
- Total contribution from cations:
\[ \text{Cations} = 8 \times \frac{1}{8} + 6 \times \frac{1}{2} = 1 + 3 = 4 \text{ cations} \]

4. **Calculating Anions in FCC**:
- In the fluorite structure, anions occupy the tetrahedral voids.
- There are 8 tetrahedral voids in an FCC unit cell, and each void contributes 1 anion.
- Total contribution from anions:
\[ \text{Anions} = 8 \text{ anions} \]

5. **Conclusion**:
- The assertion is correct: cations occupy FCC lattice points and the formula unit is \( AB_2 \).
- The reason is incorrect: there are 4 cations and 8 anions per FCC unit cell, not 6 cations and 12 anions.
- Therefore, the correct answer is that the assertion is true, but the reason is false.

### Final Answer:
- Assertion: True
- Reason: False