In F.C.C. arrangement of identical spheres, distance between two nearest octahedral void is `89.51 A`. The distance between two nearest tetrahedral voids would be ?

Explanation

To solve the problem of finding the distance between two nearest tetrahedral voids in a face-centered cubic (FCC) arrangement of identical spheres, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the FCC Structure**:
- In an FCC arrangement, the atoms are located at the corners and the centers of each face of the cube.
- The octahedral voids are located at the body center and at the edge centers, while the tetrahedral voids are located along the body diagonals of the cube.

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