2.4 gm of Mg (At. mass 24) will produce MgO equal to:

Options

A. 0.1 mole
B. 0.2 mole
C. 0.3mole
D. None

Explanation

To solve the problem of how much MgO is produced from 2.4 grams of magnesium (Mg), we can follow these steps:

### Step 1: Write the reaction
The reaction between magnesium and oxygen to form magnesium oxide (MgO) can be represented as:
\[ 2 \text{Mg} + \text{O}_2 \rightarrow 2 \text{MgO} \]
This indicates that 2 moles of magnesium react with 1 mole of oxygen to produce 2 moles of magnesium oxide.

### Step 2: Calculate the number of moles of magnesium
To find the number of moles of magnesium in 2.4 grams, we use the formula:
\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]
Given:
- Mass of Mg = 2.4 g
- Molar mass of Mg = 24 g/mol

Calculating the number of moles:
\[ \text{Number of moles of Mg} = \frac{2.4 \text{ g}}{24 \text{ g/mol}} = 0.1 \text{ moles} \]

### Step 3: Determine the number of moles of MgO produced
From the balanced equation, we see that 1 mole of Mg produces 1 mole of MgO. Therefore, the number of moles of MgO produced will be the same as the number of moles of Mg used:
\[ \text{Number of moles of MgO} = 0.1 \text{ moles} \]

### Step 4: Conclusion
Thus, 2.4 grams of magnesium will produce 0.1 moles of magnesium oxide (MgO).

### Final Answer
**0.1 moles of MgO**

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