If two gases `AB_(2)` and `B_(2)C` are mixed, following equilibria are readily established:
`AB_(2)(g)+B_(2)C(g)rarr AB_(3)(g)+BC(g)`,
`BC(g)+B_(2)C(g) rarr B_(3)C_(2)(g)`
If the reaction started only with `AB_(2)` with `B_(2)C`, then which of the following is necessarily true at equilibrium?

Options

A. `[AB_3]_(eq)=[BC]_(eq)`
B. `[AB_2]_(eq)=[B_2C]_(eq)`
C. `[AB_3]_(eq)gt[B_3C_2]_(eq)`
D. `[AB_3]_(eq)gt[BC]_(eq)`

Answer

C,D

Explanation

Let reactions is started with a mole of `AB_2` and b mole of `B_2C`
`implies` `{:(AB_2(g)+,B_2C(g)to,AB_3(g)+,BC(g)),(a,b,0,0),(a-x,b-x-y,x,x-y):}`
`{:(BC(g)+,B_2C(g)to,B_3C_3(g),),(x-y,b-x-y,y,As ygtx("why??")):}`
Clearly`[AB_3]_(eq)gt[B_3C_2]_(eq)`
and `[AB_3]_(eq)gt[BC]_(eq)`