For the reaction `1/2N_2(g)+1/2O_2(g)hArrNO(g)`. If pressure is increased by reducing the volume of container Then

Options

A. Total pressure at equilibrium will change
B. Concentration of all the component at equilibrium will change
C. Concentration of all the component at equilibrium will remain same
D. Equilibrium will shift in the forward direction

Explanation

To solve the question regarding the reaction \( \frac{1}{2}N_2(g) + \frac{1}{2}O_2(g) \rightleftharpoons NO(g) \) and the effect of increasing pressure by reducing the volume of the container, we can follow these steps:

### Step 1: Analyze the Reaction
First, we need to identify the number of moles of reactants and products in the given reaction.

- **Reactants**:
- \( \frac{1}{2}N_2 \) + \( \frac{1}{2}O_2 \) = 1 mole of reactants
- **Products**:
- \( NO \) = 1 mole of product

### Step 2: Understand the Effect of Pressure on Equilibrium
According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in pressure, the equilibrium will shift in the direction that reduces the pressure. This typically means that the reaction will favor the side with fewer moles of gas.

### Step 3: Compare Moles of Reactants and Products
In this case:
- Number of moles of reactants = 1
- Number of moles of products = 1

Since the number of moles of reactants is equal to the number of moles of products, increasing the pressure will not favor either side of the reaction.

### Step 4: Conclusion on Equilibrium Shift
Since the number of moles on both sides of the reaction is equal, the equilibrium will not shift in either direction when the pressure is increased.

### Step 5: Effect on Concentration
However, reducing the volume of the container will increase the concentration of all components because concentration is inversely proportional to volume. Hence, while the equilibrium position does not shift, the concentrations of the reactants and products will change.

### Final Answer
1. The reaction will not shift in any direction due to equal moles of reactants and products.
2. The concentration of all components at equilibrium will change due to the reduced volume.