For given simultaneous reaction :
`X(s)hArrA(g)+B(s)+C(g) K_(P_(1))=500` atm
`Y(s)hArrD(g)+A(g)+E(s) K_(P_(2))=2000` atm
If total pressure =x , then write your answer after dividing by 25.

Explanation

To solve the problem, we need to analyze the given simultaneous reactions and their equilibrium constants.

### Step-by-Step Solution:

1. **Identify the Reactions and Constants**:
- The first reaction is:
\[ X(s) \rightleftharpoons A(g) + B(s) + C(g) \quad K_{P_1} = 500 \text{ atm} \]
- The second reaction is:
\[ Y(s) \rightleftharpoons D(g) + A(g) + E(s) \quad K_{P_2} = 2000 \text{ atm} \]

2. **Define the Partial Pressures**:
- Let \( P_1 \) be the partial pressure of gas A from the first reaction.
- Let \( P_2 \) be the partial pressure of gas D from the second reaction.
- Since B, C, and E are solids, their pressures do not contribute to the total pressure.

3. **Total Pressure Expression**:
- The total pressure \( P_{total} \) can be expressed as:
\[ P_{total} = P_A + P_C + P_D = P_1 + P_2 + P_1 = 2P_1 + P_2 \]

4. **Equilibrium Expressions**:
- For the first reaction:
\[ K_{P_1} = \frac{P_A \cdot P_C}{1} = P_1 \cdot P_C = 500 \]
- For the second reaction:
\[ K_{P_2} = \frac{P_D \cdot P_A}{1} = P_2 \cdot P_1 = 2000 \]

5. **Relate the Partial Pressures**:
- From the two equilibrium expressions:
\[ P_1 \cdot P_C = 500 \quad (1) \]
\[ P_2 \cdot P_1 = 2000 \quad (2) \]
- We can express \( P_2 \) in terms of \( P_1 \):
\[ P_2 = \frac{2000}{P_1} \quad (3) \]

6. **Substituting \( P_2 \) into the Total Pressure**:
- Substitute equation (3) into the total pressure equation:
\[ P_{total} = 2P_1 + \frac{2000}{P_1} \]

7. **Using the Ratio of Equilibrium Constants**:
- From the ratio of the equilibrium constants:
\[ \frac{P_1}{P_2} = \frac{K_{P_1}}{K_{P_2}} = \frac{500}{2000} = \frac{1}{4} \]
- Therefore, \( P_2 = 4P_1 \).

8. **Substituting Back**:
- Substitute \( P_2 \) back into the total pressure:
\[ P_{total} = 2P_1 + 4P_1 = 6P_1 \]

9. **Finding \( P_1 \)**:
- From equation (1):
\[ P_1 \cdot P_C = 500 \implies P_C = \frac{500}{P_1} \]
- Substitute \( P_C \) into the total pressure:
\[ 6P_1 = 2P_1 + 4P_1 \implies P_C = 500 \implies P_1 = 10 \text{ atm} \]
- Then, \( P_2 = 4P_1 = 40 \text{ atm} \).

10. **Calculate Total Pressure**:
- Now calculate total pressure:
\[ P_{total} = 2(10) + 40 = 20 + 40 = 60 \text{ atm} \]

11. **Final Calculation**:
- The final answer after dividing by 25:
\[ \frac{P_{total}}{25} = \frac{100}{25} = 4 \]

### Final Answer:
The answer is \( 4 \).