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A 4: 1 molar mixture of He and CH4 is co...

A 4: 1 molar mixture of He and CH4 is contained in a vessel at 20 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the composition of the mixture effusing out initially?

A

`8:1`

B

`1:8`

C

`1:4`

D

`4:1`

Text Solution

Verified by Experts

The correct Answer is:
A
Molar ratio of He and `CH_4=4:1`
`:.` partial pressure `P_(He)=4/5xx20=16` bar
partial pressure `P_(CH_4)=1/5xx20=4`
`:. P_(He):P_(CH_4)=16:4`
`because` time of diffusion is same base
`r_(He)/r_(CH_4)=n_(He)/n_(CH_4)=p_(He)/p_(CH_4)xxsqrt(M_(CH_4)/M_(He))=16/4xxsqrt(16/4)=4xx2=8:1`
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