The number of moles present in 44.5 g of HSO is

Options

A. `2.1`
B. `1.2`
C. 0.9
D. 1.4

Explanation

To find the number of moles present in 44.5 g of HSO, we will follow these steps:

### Step 1: Determine the Molar Mass of HSO
- The molar mass is calculated by adding the atomic masses of all the atoms in the compound HSO.
- H (Hydrogen) has an atomic mass of approximately 1 g/mol.
- S (Sulfur) has an atomic mass of approximately 32 g/mol.
- O (Oxygen) has an atomic mass of approximately 16 g/mol.

**Calculation:**
\[ \text{Molar mass of HSO} = \text{mass of H} + \text{mass of S} + \text{mass of O} = 1 + 32 + 16 = 49 \text{ g/mol} \]

### Step 2: Use the Formula to Calculate Moles
- The formula to calculate the number of moles is:
\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]
- Here, the given mass is 44.5 g and the molar mass we calculated is 49 g/mol.

**Calculation:**
\[ \text{Number of moles} = \frac{44.5 \text{ g}}{49 \text{ g/mol}} \approx 0.908 \text{ moles} \]

### Step 3: Round the Result
- Rounding 0.908 to one decimal place gives us approximately 0.9 moles.

### Final Answer
The number of moles present in 44.5 g of HSO is approximately **0.9 moles**.

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