The number of moles present in 54.5 g of HSO is

Explanation

To find the number of moles present in 54.5 g of HSO, we can follow these steps:

### Step 1: Determine the mass of HSO
The mass of HSO given in the problem is 54.5 g.

### Step 2: Calculate the molar mass of HSO
To calculate the molar mass of HSO, we need to sum the atomic masses of its constituent elements:
- Atomic mass of Hydrogen (H) = 1 g/mol
- Atomic mass of Sulfur (S) = 32 g/mol
- Atomic mass of Oxygen (O) = 16 g/mol

Now, we add these values together:
\[ \text{Molar mass of HSO} = 1 + 32 + 16 = 49 \text{ g/mol} \]

### Step 3: Use the formula to calculate the number of moles
The formula to calculate the number of moles (n) is:
\[ n = \frac{\text{given mass}}{\text{molar mass}} \]
Substituting the values we have:
\[ n = \frac{54.5 \text{ g}}{49 \text{ g/mol}} \]

### Step 4: Perform the calculation
Now we perform the division:
\[ n = 1.112 \text{ moles} \]

### Conclusion
The number of moles present in 54.5 g of HSO is approximately 1.112 moles.

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