Consider the following figure at 500 K.Assuming ideal gas behaviour, calculate the total pressure if the barriers are removed from the compartment.Assume that the volume of barriers is negligible.

Answer

2.85 atm

Explanation

Number of moles of A,B,C and D are given as :
`n_A=(PV)/(RT)=(1xx1)/(RT),n_B=(1.5xx2)/(RT)=(3)/(RT)`
`n_C=(2.5xx4)/(RT)=(10)/(RT),n_D=(2xx3)/(RT)=(6)/(RT)`
`n=n_A+n_B+n_C+n_D=(1+3+10+6)/(RT)=20/(RT)`
Total pressure is given as
`P_("Total")=(nRT)/Vimplies P_("Total")=20/(RT)xx(RT)/7=2.85`