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A 4: 1 molar mixture of He and CH4 is co...

A 4: 1 molar mixture of He and CH4 is contained in a vessel at 20 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the composition of the mixture effusing out initially?

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The correct Answer is:
8
`n_(He//t)/n_(CH_4//t)=P_(He)/P_(CH_4)sqrt(M_(CH_4)/M_(He))=n_(He)/n_(CH_4)sqrt(M_(CH_4)/M_(He))=4/1xxsqrt(16/4)=8/1`
`:.` Required compostion `=n_(He)/n_(CH_4)=8/1 i.e. 8:1`
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