A proton when accelerated through a pote...

A proton when accelerated through a potential difference of V volt has a wavelength `lamda` associated with it. An alpha-particle in order to have the same `lamda` must be accelerated through a potential difference of

V volt

4V volt

2V volt

`V/8` volt

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The correct Answer is:

`lambda=h/(sqrt(2m_peV))`..(i)
`lambda=h/(sqrt(2m_alpha(2e)V_alpha))`..(ii)
equation (i) &(ii) we have
`2m_peV=2xx4xxm_pxx2eV_alpha`
`implies V_alpha=V/8`

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