`e//m` ratio in case of anode ray experiment is different for different gases.
The ion of gases formed after the ejection of electron are different of gas is different.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Explanation

To solve the question regarding the `e/m` ratio in the anode ray experiment and its dependence on different gases, we can break down the explanation into clear steps:

### Step-by-Step Solution:

1. **Understanding Anode Rays**:
- Anode rays are streams of positively charged ions (cations) produced when a gas at low pressure is subjected to a high voltage. This process leads to the ionization of gas atoms.

**Hint**: Remember that anode rays consist of cations formed from the ionization of gases.

2. **Ionization Process**:
- When the gas is ionized, it loses electrons and forms cations. For example, if we have gas A, it can lose electrons to form cations (A⁺).

**Hint**: The loss of electrons from the gas atoms is crucial for the formation of cations.

3. **Different Gases, Different Ions**:
- Different gases have different atomic masses and structures. Thus, when subjected to the same conditions, they will produce different cations. For instance, gas B will form cations (B⁺) which are different from those formed by gas A.

**Hint**: The type of gas determines the specific ions produced during ionization.

4. **Calculating the e/m Ratio**:
- The `e/m` ratio (charge-to-mass ratio) of the cations formed will vary depending on the mass of the cation and its charge. Since different gases produce cations of different masses and possibly different charges, the `e/m` ratio will not be constant across different gases.

**Hint**: The `e/m` ratio is influenced by both the charge and the mass of the ions produced.

5. **Conclusion**:
- Therefore, the statement that the `e/m` ratio is different for different gases is true. Additionally, since different gases produce different ions upon electron ejection, the second statement is also true. The second statement serves as a correct explanation for the first.

**Hint**: Both statements are true, and the second statement explains the first.

### Final Answer:
Both statements regarding the `e/m` ratio in the anode ray experiment and the different ions formed from different gases are true, with the second statement providing a correct explanation for the first.