Statement-1 : If an electron is located within the range of `0.1 Å` then the uncertainly in velocity is approximately `6xx10^6 m//s`
Statement-2 : Trajectory (path of motion) of above electron can be defined.
`[h=6.6xx10^(-34), m_e=9.1xx10^(-31) kg]`

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Explanation

To solve the problem, we will analyze both statements using the Heisenberg Uncertainty Principle and the information provided.

### Step-by-Step Solution:

1. **Understanding the Heisenberg Uncertainty Principle**:
The principle states that the product of the uncertainties in position (Δx) and momentum (Δp) is greater than or equal to a constant:
\[ \Delta x \cdot \Delta p \geq \frac{h}{4\pi} \]
where \( \Delta p = m \cdot \Delta v \) (momentum = mass × velocity).

2. **Given Values**:
- Planck's constant, \( h = 6.63 \times 10^{-34} \, \text{Js} \)
- Mass of electron, \( m_e = 9.1 \times 10^{-31} \, \text{kg} \)
- Position uncertainty, \( \Delta x = 0.1 \, \text{Å} = 0.1 \times 10^{-10} \, \text{m} \)

3. **Calculating the Uncertainty in Velocity (Δv)**:
Rearranging the uncertainty principle for Δv:
\[ \Delta v \geq \frac{h}{4\pi m \Delta x} \]
Substituting the values:
\[ \Delta v \geq \frac{6.63 \times 10^{-34}}{4 \times 3.14 \times 9.1 \times 10^{-31} \times (0.1 \times 10^{-10})} \]

4. **Calculating the Denominator**:
- Calculate \( 4 \times 3.14 \approx 12.56 \)
- Calculate \( 9.1 \times 10^{-31} \times 0.1 \times 10^{-10} = 9.1 \times 10^{-42} \)
- Thus, \( 4 \pi m \Delta x \approx 12.56 \times 9.1 \times 10^{-42} \approx 1.144 \times 10^{-41} \)

5. **Final Calculation**:
\[ \Delta v \geq \frac{6.63 \times 10^{-34}}{1.144 \times 10^{-41}} \approx 5.79 \times 10^{7} \, \text{m/s} \]
This value is approximately \( 6 \times 10^{6} \, \text{m/s} \), confirming Statement-1 is true.

6. **Analyzing Statement-2**:
Statement-2 claims that the trajectory of the electron can be defined. However, due to the high uncertainty in velocity (Δv), we cannot precisely define the electron's trajectory. Therefore, Statement-2 is false.

### Conclusion:
- **Statement-1** is true.
- **Statement-2** is false.

Thus, the correct answer is that Statement-1 is true and Statement-2 is false.