4.8 gm of Mg (At. mass 24) will produce MgO equal to:

Options

A. 0.1 mole
B. 0.2 mole
C. 0.5mole
D. 0.3mole

Explanation

To solve the problem of how much MgO will be produced from 4.8 grams of magnesium (Mg), we can follow these steps:

### Step 1: Write the chemical reaction
The reaction for the formation of magnesium oxide (MgO) from magnesium and oxygen is:
\[ 2 \text{Mg} + \text{O}_2 \rightarrow 2 \text{MgO} \]

### Step 2: Calculate the number of moles of magnesium
To find the number of moles of magnesium, we use the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

Given:
- Mass of magnesium (Mg) = 4.8 g
- Molar mass of magnesium = 24 g/mol

Now, we can calculate the number of moles:
\[ \text{Number of moles of Mg} = \frac{4.8 \, \text{g}}{24 \, \text{g/mol}} = 0.2 \, \text{moles} \]

### Step 3: Determine the number of moles of MgO produced
From the balanced chemical equation, we see that 1 mole of magnesium produces 1 mole of magnesium oxide (MgO). Therefore, the number of moles of MgO produced will be equal to the number of moles of magnesium reacted.

Thus, the number of moles of MgO produced is:
\[ \text{Number of moles of MgO} = 0.2 \, \text{moles} \]

### Step 4: Conclusion
The amount of magnesium oxide (MgO) produced from 4.8 grams of magnesium is 0.2 moles.

### Final Answer
The number of moles of MgO produced from 4.8 grams of magnesium is **0.2 moles**.

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