Mass of one atom of an element is 9.64×`10^(−23)`g. This is equal to :

Options

A. 5.87u
B. 58u
C. 78u
D. 45u

Explanation

To find the mass of one mole of the element given the mass of one atom, we can use Avogadro's number. Here’s a step-by-step solution:

### Step 1: Understand the relationship between mass of one atom and mass of one mole
The mass of one mole of atoms (in grams) can be calculated using the formula:
\[ \text{Mass of one mole} = \text{Mass of one atom} \times \text{Avogadro's number} \]

### Step 2: Identify the values
- Mass of one atom = \(9.64 \times 10^{-23}\) g
- Avogadro's number (\(N_A\)) = \(6.02 \times 10^{23}\) atoms/mole

### Step 3: Substitute the values into the formula
\[ \text{Mass of one mole} = (9.64 \times 10^{-23} \, \text{g}) \times (6.02 \times 10^{23} \, \text{atoms/mole}) \]

### Step 4: Perform the multiplication
Calculating the multiplication:
\[ \text{Mass of one mole} = 9.64 \times 6.02 \times 10^{-23} \times 10^{23} \]
\[ = 9.64 \times 6.02 \, \text{g} \]

### Step 5: Calculate \(9.64 \times 6.02\)
\[ 9.64 \times 6.02 = 58.0 \, \text{g} \]

### Step 6: Conclusion
Thus, the mass of one mole of the element is \(58 \, \text{g}\).

### Final Answer
The mass of one atom of the element is equal to \(58 \, \text{g}\).

---