2.2 gm of Mg (At. mass 24) will produce MgO equal to:

Options

A. 2.1 mole
B. 0.09mole
C. 0.25mole
D. 1.3mole

Explanation

To solve the problem of how much magnesium oxide (MgO) will be produced from 2.2 grams of magnesium (Mg), we can follow these steps:

### Step 1: Write the chemical reaction
The reaction between magnesium and oxygen to form magnesium oxide can be represented as:
\[ 2 \text{Mg} + \text{O}_2 \rightarrow 2 \text{MgO} \]
This indicates that 2 moles of magnesium react with 1 mole of oxygen to produce 2 moles of magnesium oxide.

### Step 2: Calculate the number of moles of magnesium
To find the number of moles of magnesium in 2.2 grams, we use the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
Given:
- Mass of magnesium = 2.2 g
- Molar mass of magnesium = 24 g/mol

Now, substituting the values:
\[ \text{Number of moles of Mg} = \frac{2.2 \, \text{g}}{24 \, \text{g/mol}} \]
Calculating this gives:
\[ \text{Number of moles of Mg} = 0.09167 \, \text{mol} \approx 0.09 \, \text{mol} \]

### Step 3: Relate moles of magnesium to moles of magnesium oxide
From the balanced chemical equation, we see that:
- 1 mole of magnesium produces 1 mole of magnesium oxide.

Thus, if we have 0.09 moles of magnesium, it will produce the same amount of magnesium oxide:
\[ \text{Number of moles of MgO} = 0.09 \, \text{mol} \]

### Step 4: Conclusion
Therefore, 2.2 grams of magnesium will produce approximately 0.09 moles of magnesium oxide (MgO).

### Final Answer
The amount of MgO produced from 2.2 grams of Mg is approximately 0.09 moles.

---