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Match the increasing orders given in column I with the property given in column II
`{:("Column-I","Column-II"),((A)Na^+ ltF^(-) ltO^(2-)ltN^(3-),(p)"Electronegativity"),((B)Li^(+)ltNa^(+)ltK^(+)ltRb^(+)ltCs^(+),(q)"Nuclear charge"),((C )"O S F Cl",(r)"Size"),((D)Cl^(-)ltK^(+)ltCa^(2+)ltSc^(2+),(s)"Electron affinity"),(,(t)"Ionisation energy"):}`

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To solve the problem of matching the increasing orders from Column I with the properties in Column II, we will analyze each option step by step. ### Step 1: Analyze Column A **Given Order:** Na+ < F- < O2- < N3- 1. **Identify the number of electrons:** - Na+: 11 - 1 = 10 electrons - F-: 9 + 1 = 10 electrons - O2-: 8 + 2 = 10 electrons - N3-: 7 + 3 = 10 electrons All species are isoelectronic with 10 electrons. 2. **Match with properties:** - **Electronegativity:** Inversely proportional to negative charge. As we move from left to right, negative charge increases, so electronegativity decreases. **Not a match.** - **Nuclear charge:** Increases with the number of protons. Na has 11, F has 9, O has 8, N has 7. **Not a match.** - **Size:** Size increases with negative charge. As we move from left to right, size increases. **Match with Size (R).** - **Electron affinity:** Inversely proportional to negative charge. As negative charge increases, electron affinity decreases. **Not a match.** - **Ionization energy:** Inversely proportional to negative charge. As negative charge increases, ionization energy decreases. **Not a match.** **Conclusion for A:** Matches with **R (Size)**. ### Step 2: Analyze Column B **Given Order:** Li+ < Na+ < K+ < Rb+ < Cs+ 1. **Properties:** - **Electronegativity:** Decreases down the group. **Not a match.** - **Nuclear charge:** Increases down the group. **Match with Nuclear charge (Q).** - **Size:** Increases down the group. **Match with Size (R).** - **Electron affinity:** Decreases down the group. **Not a match.** - **Ionization energy:** Decreases down the group. **Not a match.** **Conclusion for B:** Matches with **Q (Nuclear charge)** and **R (Size)**. ### Step 3: Analyze Column C **Given Order:** O < S < F < Cl 1. **Properties:** - **Electronegativity:** F > Cl > S > O. **Not a match.** - **Nuclear charge:** O (8), S (16), F (9), Cl (17). **Not a match.** - **Size:** F is smaller than O, so this order is incorrect. **Not a match.** - **Electron affinity:** Cl > F > S > O. **Match with Electron affinity (S).** - **Ionization energy:** F > Cl > S > O. **Not a match.** **Conclusion for C:** Matches with **S (Electron affinity)**. ### Step 4: Analyze Column D **Given Order:** Cl- < K+ < Ca2+ < Sc2+ 1. **Properties:** - **Electronegativity:** Cl has high electronegativity, while K, Ca, and Sc have lower. **Not a match.** - **Nuclear charge:** K (19), Ca (20), Sc (21). **Match with Nuclear charge (Q).** - **Size:** Size increases with positive charge. **Not a match.** - **Electron affinity:** Cl has high electron affinity; K, Ca, and Sc have lower. **Match with Electron affinity (S).** - **Ionization energy:** Increases with positive charge. **Match with Ionization energy (T).** **Conclusion for D:** Matches with **Q (Nuclear charge)**, **S (Electron affinity)**, and **T (Ionization energy)**. ### Final Matching: - A: R (Size) - B: Q (Nuclear charge), R (Size) - C: S (Electron affinity) - D: Q (Nuclear charge), S (Electron affinity), T (Ionization energy)

To solve the problem of matching the increasing orders from Column I with the properties in Column II, we will analyze each option step by step. ### Step 1: Analyze Column A **Given Order:** Na+ < F- < O2- < N3- 1. **Identify the number of electrons:** - Na+: 11 - 1 = 10 electrons - F-: 9 + 1 = 10 electrons ...
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