How many of g of `S` are required to produce `10` moles and `10` g of `H_(2)SO_(4)` respectively ?

Options

A. 240g,14.58g
B. 140g, 2.45g
C. 320g, 3.265g
D. 120g, 3.45g

Answer

To solve the problem of how many grams of sulfur (S) are required to produce 10 moles and 10 grams of H₂SO₄ respectively, we can follow these steps:

### Step 1: Determine the amount of sulfur in 10 moles of H₂SO₄
1. **Molar Mass of H₂SO₄**: The molar mass of sulfuric acid (H₂SO₄) is 98 g/mol.
2. **Sulfur Content**: Each mole of H₂SO₄ contains 1 atom of sulfur. The atomic mass of sulfur (S) is 32 g/mol.
3. **Calculate sulfur in 10 moles**:
\[ \text{Mass of S in 10 moles of H₂SO₄} = 10 \, \text{moles} \times 32 \, \text{g/mol} = 320 \, \text{g} \]

### Step 2: Determine the amount of sulfur in 10 grams of H₂SO₄
1. **Calculate the fraction of sulfur in H₂SO₄**:
- The mass of sulfur in 98 g of H₂SO₄ is 32 g.
- Therefore, the fraction of sulfur in H₂SO₄ is:
\[ \text{Fraction of S} = \frac{32 \, \text{g}}{98 \, \text{g}} \]
2. **Calculate the mass of sulfur in 10 g of H₂SO₄**:
\[ \text{Mass of S in 10 g of H₂SO₄} = \left(\frac{32}{98}\right) \times 10 \, \text{g} \approx 3.265 \, \text{g} \]

### Final Results
- To produce **10 moles of H₂SO₄**, **320 g of sulfur** is required.
- To produce **10 g of H₂SO₄**, approximately **3.265 g of sulfur** is required.