How many of g of S are required to produce 20 moles and 10 g of `H_(2)SO_(4)` respectively?

Options

A. 640g,3.265g
B. 320g,3.265g
C. 120g,2.265g
D. 230g,1.265g

Explanation

To solve the question of how many grams of sulfur (S) are required to produce 20 moles and 10 grams of \( H_2SO_4 \), we will follow these steps:

### Step 1: Determine the amount of sulfur in 20 moles of \( H_2SO_4 \)

1. **Identify the molar mass of sulfur**: The atomic mass of sulfur (S) is 32 g/mol.
2. **Identify the number of moles of \( H_2SO_4 \)**: We need to find the sulfur required for 20 moles of \( H_2SO_4 \).
3. **Calculate the sulfur required**:
- Each mole of \( H_2SO_4 \) contains 1 atom of sulfur.
- Therefore, 20 moles of \( H_2SO_4 \) will contain 20 moles of sulfur.
- The mass of sulfur required = Number of moles × Molar mass of sulfur
- Mass of sulfur = \( 20 \, \text{moles} \times 32 \, \text{g/mol} = 640 \, \text{g} \)

### Step 2: Determine the amount of sulfur in 10 grams of \( H_2SO_4 \)

1. **Identify the molar mass of \( H_2SO_4 \)**: The molar mass of \( H_2SO_4 \) is 98 g/mol.
2. **Calculate the number of moles in 10 grams of \( H_2SO_4 \)**:
- Moles of \( H_2SO_4 = \frac{\text{mass}}{\text{molar mass}} = \frac{10 \, \text{g}}{98 \, \text{g/mol}} \approx 0.102 \, \text{moles} \)
3. **Calculate the sulfur required**:
- Each mole of \( H_2SO_4 \) contains 1 atom of sulfur.
- Therefore, the moles of sulfur required = Moles of \( H_2SO_4 \) = 0.102 moles.
- Mass of sulfur = Number of moles × Molar mass of sulfur
- Mass of sulfur = \( 0.102 \, \text{moles} \times 32 \, \text{g/mol} \approx 3.265 \, \text{g} \)

### Final Answer:
- To produce 20 moles of \( H_2SO_4 \), 640 g of sulfur is required.
- To produce 10 g of \( H_2SO_4 \), approximately 3.265 g of sulfur is required.