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In the valence bond theory, hybridisatio...

In the valence bond theory, hybridisation of orbitals is an integral part of bond formation.Hybridisation consists of mixing or linear combination of the "pure" atomic orbitals in such a way as to form new hybrid orbitals such as `sp, sp^2, sp^3, sp^3d , sp^3d^2` etc.
Now answer the following questions :
Which one of the following molecular geometrices (i.e. shapes) is not possible for the `sp^3d^3` hybridisation ?

A

Capped octahedral

B

Octahedral

C

Square planar

D

Square pyramidral

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The correct Answer is:
To determine which molecular geometries are not possible for the `sp^3d^3` hybridization, we can follow these steps: ### Step 1: Understand Hybridization Hybridization involves the mixing of atomic orbitals to form new hybrid orbitals. For `sp^3d^3` hybridization, we are mixing: - 1 s orbital - 3 p orbitals - 3 d orbitals This results in the formation of **seven hybrid orbitals**. ### Step 2: Determine the Steric Number The steric number is calculated as the sum of the number of bond pairs and lone pairs around the central atom. For `sp^3d^3` hybridization, the steric number is **7**. ### Step 3: Identify Possible Geometries The molecular geometry corresponding to a steric number of 7 is: - **Pentagonal bipyramidal**: This geometry has five atoms in a plane and two atoms above and below this plane. ### Step 4: Evaluate Other Geometries For `sp^3d^3` hybridization, we need to check which geometries are not possible: 1. **Octahedral**: This geometry corresponds to a steric number of 6, which is not applicable here. 2. **Square planar**: This geometry also corresponds to a steric number of 4, which is not applicable here. 3. **Square pyramidal**: This geometry corresponds to a steric number of 5, which is not applicable here. ### Conclusion The geometries that are **not possible** for `sp^3d^3` hybridization are: - **Octahedral** - **Square planar** - **Square pyramidal** ### Final Answer The molecular geometries that are not possible for `sp^3d^3` hybridization are **octahedral, square planar, and square pyramidal**. ---

To determine which molecular geometries are not possible for the `sp^3d^3` hybridization, we can follow these steps: ### Step 1: Understand Hybridization Hybridization involves the mixing of atomic orbitals to form new hybrid orbitals. For `sp^3d^3` hybridization, we are mixing: - 1 s orbital - 3 p orbitals - 3 d orbitals ...
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In the valence bond theory, hybridisation of orbitals is an integral part of bond formation.Hybridisation consists of mixing or linear combination of the "pure" atomic orbitals in such a way as to form new hybrid orbitals such as sp, sp^2, sp^3, sp^3d , sp^3d^2 etc. Now answer the following questions : Which of the following atomic orbitals does not participitate in trigonal bipyramidal hybridisation i.e. sp^3d hybridisation ?

In the valence bond theory, hybridisation of orbitals is an integral part of bond formation.Hybridisation consists of mixing or linear combination of the "pure" atomic orbitals in such a way as to form new hybrid orbitals such as sp, sp^2, sp^3, sp^3d , sp^3d^2 etc. Now answer the following questions : Which of the following are isostructural ? {:(NO_3^(-),CO_3^(2-),CIO_3^(-),SO_3,XeO_3),((I),(II),(III),(IV),"(V)"):}

sp^(3)d hybridisation has

Sp^3d Hybridisation

Which one of the following does not have sp^(2) hybridised carbon ?

Which one of the following does not have sp^(2) hybridised carbon ?

Which one of the following does not have sp^(2) hybridised carbon ?

Which of the following have sp^(3) d hybridisation ? .

The d-orbitals involved in sp^(3)d hybridisation is:

Which one of the following compounds has sp^(2) hybridisation ? .

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