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In the valence bond theory, hybridisatio...

In the valence bond theory, hybridisation of orbitals is an integral part of bond formation.Hybridisation consists of mixing or linear combination of the "pure" atomic orbitals in such a way as to form new hybrid orbitals such as `sp, sp^2, sp^3, sp^3d , sp^3d^2` etc.
Now answer the following questions :
Which of the following atomic orbitals does not participitate in trigonal bipyramidal hybridisation i.e. `sp^3d` hybridisation ?

A

s

B

`d_(x^2-y^2)`

C

`p_x`

D

`p_y`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which atomic orbital does not participate in trigonal bipyramidal hybridization (sp³d hybridization), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Hybridization**: - Hybridization involves the mixing of atomic orbitals to form new hybrid orbitals. In the case of sp³d hybridization, five atomic orbitals are involved: one s orbital, three p orbitals, and one d orbital. 2. **Identifying the Orbitals Involved**: - For sp³d hybridization, the participating orbitals are: - 1 s orbital (1s) - 3 p orbitals (typically px, py, and pz) - 1 d orbital (from the d subshell) 3. **Geometry of Trigonal Bipyramidal**: - The trigonal bipyramidal geometry consists of three atoms forming a triangle in one plane and two additional atoms positioned above and below this plane. This arrangement minimizes electron repulsion. 4. **Choosing the d Orbital**: - Among the d orbitals (dxy, dyz, dxz, dx²-y², dz²), the dz² orbital is typically used in sp³d hybridization because it is oriented along the z-axis and does not have lobes in the xy-plane, thus minimizing repulsion with the other orbitals. 5. **Identifying the Non-Participating Orbital**: - The d orbital that does not participate in this hybridization is dx²-y². This is because it has lobes in the xy-plane, which would lead to increased repulsion with the p orbitals that lie in the same plane. 6. **Conclusion**: - Therefore, the atomic orbital that does not participate in trigonal bipyramidal hybridization (sp³d hybridization) is **dx²-y²**. ### Final Answer: The atomic orbital that does not participate in trigonal bipyramidal hybridization is **dx²-y²**.

To determine which atomic orbital does not participate in trigonal bipyramidal hybridization (sp³d hybridization), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Hybridization**: - Hybridization involves the mixing of atomic orbitals to form new hybrid orbitals. In the case of sp³d hybridization, five atomic orbitals are involved: one s orbital, three p orbitals, and one d orbital. 2. **Identifying the Orbitals Involved**: ...
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In the valence bond theory, hybridisation of orbitals is an integral part of bond formation.Hybridisation consists of mixing or linear combination of the "pure" atomic orbitals in such a way as to form new hybrid orbitals such as sp, sp^2, sp^3, sp^3d , sp^3d^2 etc. Now answer the following questions : Which one of the following molecular geometrices (i.e. shapes) is not possible for the sp^3d^3 hybridisation ?

In the valence bond theory, hybridisation of orbitals is an integral part of bond formation.Hybridisation consists of mixing or linear combination of the "pure" atomic orbitals in such a way as to form new hybrid orbitals such as sp, sp^2, sp^3, sp^3d , sp^3d^2 etc. Now answer the following questions : Which of the following are isostructural ? {:(NO_3^(-),CO_3^(2-),CIO_3^(-),SO_3,XeO_3),((I),(II),(III),(IV),"(V)"):}

sp^(3)d hybridisation has

Which of the following have sp^(3) d hybridisation ? .

Which of the following species has sp^(3) hybridisation.

The d-orbitals involved in sp^(3)d hybridisation is:

The central atom assume sp^(3) hybridisation in:

In which of the following the central atom does not use sp^3 hybrid orbitals in its bonding

In which of the following the central atom does not use sp^(2) hybrid orbitals in its bonding

Which one of the following does not have sp^(2) hybridised carbon ?

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