`N_2` has greater bond energy than `N_(2)^(+)` but `O_2` has lower bond dissociation energy than `O_(2)^(+)`. Explain.

Options

A. Bond order is reduced when `O_2` is ionized to `O_2^(+)` and bond order is increased when `N_2` is ionized to `N_2^+`
B. Bond order is increased when `O_2` is ionized to `O_2^(+)` and bond order is decreased when `N_2` is ionized to `N_2^+`
C. Bond order is decreased when `O_2` is ionized to `O_2^(+)` and bond order is decreased when `N_2` is ionized to `N_2^+`
D. None of these

Answer

B

Explanation

`{:(" Species" ,N_2,N_2^+,O_2,O_2^+),("Bond Order",3,2.5,2,2.5):}`