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1.49g of ammonia at STP occupies a volum...

1.49g of ammonia at STP occupies a volume of 2.48 `dm^3` calculate the molar mass of ammonia.

A

13.45g/mol

B

17.45g/mol

C

16.48g/mol

D

None of these

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The correct Answer is:
To calculate the molar mass of ammonia (NH₃) using the given data, we can follow these steps: ### Step 1: Understand the Given Data We have: - Mass of ammonia (NH₃) = 1.49 g - Volume occupied by ammonia at STP = 2.48 dm³ (which is equivalent to 2.48 L) ### Step 2: Use the Ideal Gas Law Concept At Standard Temperature and Pressure (STP), one mole of any ideal gas occupies 22.4 L. ### Step 3: Calculate the Number of Moles of Ammonia To find the number of moles (n) of ammonia, we can use the formula: \[ n = \frac{\text{Volume}}{\text{Molar Volume at STP}} \] Where the molar volume at STP is 22.4 L. Substituting the values: \[ n = \frac{2.48 \, \text{L}}{22.4 \, \text{L/mol}} \] ### Step 4: Perform the Calculation Calculating the number of moles: \[ n = \frac{2.48}{22.4} \approx 0.1107 \, \text{mol} \] ### Step 5: Calculate the Molar Mass of Ammonia The molar mass (M) can be calculated using the formula: \[ M = \frac{\text{Mass}}{\text{Number of Moles}} \] Substituting the known values: \[ M = \frac{1.49 \, \text{g}}{0.1107 \, \text{mol}} \] ### Step 6: Perform the Calculation Calculating the molar mass: \[ M \approx \frac{1.49}{0.1107} \approx 13.45 \, \text{g/mol} \] ### Final Answer The molar mass of ammonia (NH₃) is approximately **13.45 g/mol**. ---

To calculate the molar mass of ammonia (NH₃) using the given data, we can follow these steps: ### Step 1: Understand the Given Data We have: - Mass of ammonia (NH₃) = 1.49 g - Volume occupied by ammonia at STP = 2.48 dm³ (which is equivalent to 2.48 L) ### Step 2: Use the Ideal Gas Law Concept ...
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