Match the following :
`{:("Column-I","Column-II"),("Species","Characteristics of central atom"),((A)IBr_2^(-),(p)sp^3d^2",2 lone pairs"),((B)XeF_5^(-),(q)sp^3d",1 lone pair"),((C )ICl_4^(-),(r)sp^3d^3",1 lone pair "),((D )IF_6^(-),(s)sp^3d^3", 2 lone pair"),(,(t)sp^3d",3 lone pairs"):}`

Explanation

To solve the problem of matching the species in Column-I with their characteristics in Column-II, we will follow a systematic approach to determine the hybridization and the number of lone pairs for each species.

### Step-by-Step Solution:

1. **Identify the Central Atom and Valence Electrons**:
- For each species, identify the central atom and count its valence electrons.

2. **Apply the Hybridization Formula**:
- Use the formula for hybridization:
\[ \text{Hybridization} = \frac{\text{Valence Electrons of Central Atom} + \text{Number of Surrounding Monovalent Atoms} + \text{Negative Charge} - \text{Positive Charge}}{2} \]

3. **Determine Bond Pairs and Lone Pairs**:
- Calculate the number of bond pairs based on the number of surrounding atoms.
- Determine the number of lone pairs by subtracting the number of bond pairs from the total hybridization number.

4. **Match with Column-II**:
- Based on the calculated hybridization and lone pairs, match each species with its corresponding characteristics in Column-II.

### Detailed Calculations:

**(A) IBr₂⁻**:
- Central Atom: Iodine (I)
- Valence Electrons: 7
- Surrounding Atoms: 2 (Br)
- Charge: -1
- Calculation:
\[ \text{Hybridization} = \frac{7 + 2 + 1}{2} = \frac{10}{2} = 5 \quad (\text{sp}^3\text{d}) \]
- Bond Pairs: 2 (from 2 Br)
- Lone Pairs: \(5 - 2 = 3\)
- Match: **(A) → (t)**

**(B) XeF₅⁻**:
- Central Atom: Xenon (Xe)
- Valence Electrons: 8
- Surrounding Atoms: 5 (F)
- Charge: -1
- Calculation:
\[ \text{Hybridization} = \frac{8 + 5 + 1}{2} = \frac{14}{2} = 7 \quad (\text{sp}^3\text{d}^3) \]
- Bond Pairs: 5
- Lone Pairs: \(7 - 5 = 2\)
- Match: **(B) → (s)**

**(C) ICl₄⁻**:
- Central Atom: Iodine (I)
- Valence Electrons: 7
- Surrounding Atoms: 4 (Cl)
- Charge: -1
- Calculation:
\[ \text{Hybridization} = \frac{7 + 4 + 1}{2} = \frac{12}{2} = 6 \quad (\text{sp}^3\text{d}^2) \]
- Bond Pairs: 4
- Lone Pairs: \(6 - 4 = 2\)
- Match: **(C) → (p)**

**(D) IF₆⁻**:
- Central Atom: Iodine (I)
- Valence Electrons: 7
- Surrounding Atoms: 6 (F)
- Charge: -1
- Calculation:
\[ \text{Hybridization} = \frac{7 + 6 + 1}{2} = \frac{14}{2} = 7 \quad (\text{sp}^3\text{d}^3) \]
- Bond Pairs: 6
- Lone Pairs: \(7 - 6 = 1\)
- Match: **(D) → (r)**

### Final Matches:
- (A) → (t)
- (B) → (s)
- (C) → (p)
- (D) → (r)

### Summary of Matches:
- A → t
- B → s
- C → p
- D → r