How many maximum atoms lie in the same plane in the structure of methylenesulphurtetrafluoride `(CH_2SF_4)` ?

Explanation

To determine how many maximum atoms lie in the same plane in the structure of methylenesulphurtetrafluoride (CH₂SF₄), we can follow these steps:

### Step 1: Understand the Molecular Structure
Methylene sulfur tetrafluoride consists of a sulfur atom (S) bonded to a carbon atom (C), which is further bonded to two hydrogen atoms (H) and four fluorine atoms (F).

### Step 2: Draw the Lewis Structure
1. Start by placing the sulfur atom at the center.
2. Attach the carbon atom to the sulfur with a double bond.
3. Attach two hydrogen atoms to the carbon atom.
4. Attach four fluorine atoms to the sulfur atom, with two in the equatorial position and two in the axial position.

### Step 3: Identify the Plane of Atoms
In the structure of CH₂SF₄:
- The carbon atom (C) and the two hydrogen atoms (H) are in the same plane.
- The two fluorine atoms (F) in the equatorial position also lie in this plane.

### Step 4: Count the Atoms in the Same Plane
Now, we can count the total number of atoms in the same plane:
- 1 Carbon (C)
- 2 Hydrogens (H)
- 1 Sulfur (S)
- 2 Fluorines (F)

Adding these together gives:
1 (C) + 2 (H) + 1 (S) + 2 (F) = 6 atoms.

### Conclusion
The maximum number of atoms that lie in the same plane in the structure of methylenesulphurtetrafluoride (CH₂SF₄) is **6**.

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