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If the dipole moment of AB molecule is g...

If the dipole moment of AB molecule is given by 1.2 D and A - B the bond length is `1­Å` then `%` ionic character of the bond is [Given : 1 debye `=10^(-18)` esu. Cm]

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The correct Answer is:
`50%`

`N_("cal".)=4.8xx10^(-10)e.s.uxx10^(-8)`cm
`=4.8xx10^(-18)`esu cm
=4.8 D
`:.` % ionic character `=2.4/4.8xx100=50%`
`:.` % co-valent character =50%
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