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Co^(2+)(aq.)+SCN^(-)(aq.)to"Complex"(X) ...

`Co^(2+)(aq.)+SCN^(-)(aq.)to"Complex"(X)`
`Ni^(2+)(aq.)+"Dimethylglyoxime"overset(NH_4OH)to"Complex"(Y)`.
The coordination number of cobalt and nickel in complexes X and Y is four.
The IUPAC name of the complexes (X) and (Y) are respectively:

A

(X) is paramagnetic with two unpaired electrons

B

(Y) is diamagnetic and shows intermolecular H-bonding

C

(X) is paramagnetic with three unpaired electrons and (Y) is diamagnetic

D

(X) and (Y) both are diamagnetic

Text Solution

Verified by Experts

The correct Answer is:
C

`x=[Co(SCN)_4]^(2-)`, cobalt is in +2 oxidation state and `SCN^-` is weak field ligand. So,

`Y=[Ni(dmg)_2]`:Nickel is in +2 oxidation state and dmg is chelating ligand. So,

`[ni(dmg)_2]` shows intra molecular H-bonding as shown below .
Reaction involved :
`Co^(2+)(aq)+4SCN^(-)(aq)to[Co(SCN)_4]^(2-)(aq)` blue colour complex.
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