Match the complexed listed column `-I` with type of hybridisation listed in column `-II` and select the correct answer using the code given below the lists `:`
`{:(,"Column"-I,,"Column"-II,),((a),[AuF_(4)]^(-),,(p)" "dsp^(2)"hybridisation",),((b),[Cu(CN)_(4)]^(3-),,(q)" "sp^(3)"hybridisation",),((c ),[Co(NH_(3))_(6)]^(3+),,(r)" "sp^(3)d^(2)"hybridisation",),((d),[Fe(H_(2)O)_(5)NO]^(2+),,(s)" "d^(2)sp^(3)"hybridisation",):}`

Answer

A-p ; B-q ; C-r,t ; D-r

Explanation

(A)`dsp^2` hybridisation, Au is in +3 oxidation state (`5d^8` configuration ) and complex is diamagnetic.
(B)`sp^3` hybridisation, Cu is in +1 oxidation state and complex is diamagnetic. `CN^-` is strong fiel ligand but no empty d-orbtitals is available for `dsp^2` hybridisation.
(C )`sp^3d^2` hybridisation, Ni is in +2 oxidation state and complex is paramagnetic with two unpaired electron.
(D)`sp^3d^2` hybridisation with Fe in +1 oxidation state and paramagnetic with three unpaired electrons.