One of the products of the following reaction `KCNO+(NH_4)_2SO_4oversetDeltato is:`

Options

A. `NH_4CO_2`
B. `NH_4NO_5`
C. `NH_2 - CO - NH_2`
D. both `N_2` and `NO_2`

Explanation

To solve the question regarding the reaction between potassium cyanate (KCNO) and ammonium sulfate ((NH₄)₂SO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in the reaction are potassium cyanate (KCNO) and ammonium sulfate ((NH₄)₂SO₄).

2. **Write the Initial Reaction**: When potassium cyanate is heated with ammonium sulfate, the initial reaction can be represented as:
\[ 2 \text{KCNO} + \text{(NH}_4)_2\text{SO}_4 \rightarrow 2 \text{NH}_4\text{CNO} + \text{K}_2\text{SO}_4 \]
Here, ammonium cyanate (NH₄CNO) and potassium sulfate (K₂SO₄) are formed.

3. **Evaporate to Dryness**: The next step involves evaporating the solution to dryness. This process leads to the formation of ammonium cyanate (NH₄CNO).

4. **Rearrangement of Ammonium Cyanate**: The ammonium cyanate formed undergoes rearrangement. This rearrangement is known as the conversion of ammonium cyanate to urea.

5. **Final Product Formation**: The rearrangement of ammonium cyanate results in the formation of urea (NH₂CONH₂). Thus, the final product of the reaction is:
\[ \text{Urea (NH}_2\text{CONH}_2\text{)} \]

### Conclusion:
The product of the reaction between potassium cyanate and ammonium sulfate upon heating is urea (NH₂CONH₂).