The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the order

Options

A. `S_2O_6^(2-)ltSO_4^(2-)ltSO_3^(2-)`
B. `S_2O_4^(2-) lt SO_3^(2-) lt S_2O_6^(2-)`
C. `SO_3^(2-) lt S_2O_4^(2-)lt S_2O_6^(2-)`
D. `S_2O_4^(2-) lt S_2O_6^(2-) lt SO_3^(2-)`

Answer

2

Explanation

O.S. of S in `SO_3^(2-)=+4`
O.S. of S in `S_2O_4^(2-)=+3`
O.S. of S in `S_2O_6^(2-)=+5`
(None of these contains peroxide linkage. )
The correct order of increasing O.S. is ,
`S_2O_4^(2-) lt SO_3^(2-) lt S_2O_6^(2-)`