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3.49g of ammonia at STP occupies a volum...

3.49g of ammonia at STP occupies a volume of 4.48 `dm^3` calculate the molar mass of ammonia.

A

17.45 g/mol

B

13.45 g/mol

C

15.59 g/mol

D

None of these

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The correct Answer is:
To calculate the molar mass of ammonia (NH₃) given that 3.49 g of ammonia occupies a volume of 4.48 dm³ at STP, we can follow these steps: ### Step 1: Understand the relationship between volume and molar mass at STP At standard temperature and pressure (STP), 1 mole of any ideal gas occupies a volume of 22.4 liters (or 22.4 dm³). ### Step 2: Convert the given volume to liters The volume of ammonia given is 4.48 dm³, which is equivalent to 4.48 liters. ### Step 3: Calculate the number of moles of ammonia Using the volume of ammonia and the molar volume at STP, we can calculate the number of moles of ammonia (n) using the formula: \[ n = \frac{\text{Volume of gas at STP}}{\text{Molar volume at STP}} \] \[ n = \frac{4.48 \, \text{liters}}{22.4 \, \text{liters/mole}} \] ### Step 4: Perform the calculation Calculating the number of moles: \[ n = \frac{4.48}{22.4} = 0.2 \, \text{moles} \] ### Step 5: Calculate the molar mass of ammonia The molar mass (M) can be calculated using the formula: \[ M = \frac{\text{mass of gas}}{\text{number of moles}} \] Given that the mass of ammonia is 3.49 g, we can substitute the values: \[ M = \frac{3.49 \, \text{g}}{0.2 \, \text{moles}} \] ### Step 6: Perform the calculation Calculating the molar mass: \[ M = \frac{3.49}{0.2} = 17.45 \, \text{g/mol} \] ### Conclusion The molar mass of ammonia (NH₃) is approximately 17.45 g/mol. ---

To calculate the molar mass of ammonia (NH₃) given that 3.49 g of ammonia occupies a volume of 4.48 dm³ at STP, we can follow these steps: ### Step 1: Understand the relationship between volume and molar mass at STP At standard temperature and pressure (STP), 1 mole of any ideal gas occupies a volume of 22.4 liters (or 22.4 dm³). ### Step 2: Convert the given volume to liters The volume of ammonia given is 4.48 dm³, which is equivalent to 4.48 liters. ...
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