How much mass of sodium acetate is required to make 230 mL of 0.575 molar aqueous solution?

Options

A. 11.79g
B. 10.84g
C. 25.5g
D. 15.38g

Explanation

To solve the problem of how much mass of sodium acetate is required to make 230 mL of a 0.575 molar aqueous solution, we can follow these steps:

### Step 1: Understand the formula for molarity
Molarity (M) is defined as the number of moles of solute per liter of solution. The formula is:
\[ M = \frac{\text{number of moles of solute}}{\text{volume of solution in liters}} \]

### Step 2: Convert volume from mL to L
We need to convert the volume of the solution from milliliters to liters:
\[ 230 \, \text{mL} = 230 \times 10^{-3} \, \text{L} = 0.230 \, \text{L} \]

### Step 3: Calculate the number of moles of sodium acetate needed
Using the molarity formula, we can rearrange it to find the number of moles:
\[ \text{number of moles} = M \times \text{volume in L} \]
Substituting the values:
\[ \text{number of moles} = 0.575 \, \text{mol/L} \times 0.230 \, \text{L} \]
\[ \text{number of moles} = 0.13225 \, \text{mol} \]

### Step 4: Find the molar mass of sodium acetate
The molar mass of sodium acetate (C₂H₃O₂Na) is given as:
\[ \text{Molar mass} = 82 \, \text{g/mol} \]

### Step 5: Calculate the mass of sodium acetate required
We can use the number of moles to find the mass using the formula:
\[ \text{mass} = \text{number of moles} \times \text{molar mass} \]
Substituting the values:
\[ \text{mass} = 0.13225 \, \text{mol} \times 82 \, \text{g/mol} \]
\[ \text{mass} = 10.84 \, \text{g} \]

### Conclusion
The mass of sodium acetate required to make 230 mL of a 0.575 molar solution is **10.84 grams**.

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