A crystalline solid (A) reacts with hydrogen gas to form a monoatomic gas (B) and a highly associated liquid ( C).(A) is soluble in water and undergoes hydroloysis slowly to form (B),(C ) and a diatomic gas (D).When pure and dry (D) is subjected to a silent electric discharge an another pale blue gas (E) is produced which like (A) also acts a strong oxidising agent.(E) dissolves in potassium hydroxide forming an orange coloured solid which is paramagnetic in nature. (A) reacts with `IF_5, SbF_5, PF_5` etc to form the addition compounds. (C ) forms an addition compound (F) with KF with when electrolysed in molten state forms a most reactive gas (G).(B) and (G) (taken in 2:1) ratio when heated in nickel tube at `400^@ C` and 6 atm pressure forms (A).The first ionization energy `(IE_1)` of (B) is fairly close to (D).
Which of the correct choice for (D) and (E) ?

Options

A. (E) reacts with dry iodine to form `I_2O_5`
B. A filter paper soaked in alcoholic benzidine becomes brown when brought in contact with (E)
C. (D) is prepared by Brin's process
D. (B) and (C ) both

Explanation

To solve the question, we need to analyze the information provided step by step:

1. **Identify the Crystalline Solid (A)**:
- The crystalline solid (A) reacts with hydrogen gas to form a monoatomic gas (B) and a highly associated liquid (C).
- Given that (B) is a monoatomic gas, it could be a noble gas. However, since (A) is soluble in water and undergoes hydrolysis, it suggests that (A) is likely a halide or a similar compound that can release a monoatomic gas upon reaction.

2. **Formation of Monoatomic Gas (B)**:
- The reaction of (A) with hydrogen gas produces (B) and (C). If we consider (A) to be xenon difluoride (XeF2), then upon reaction with hydrogen, it can produce xenon (B) and hydrofluoric acid (C).

3. **Hydrolysis of (A)**:
- When (A) undergoes hydrolysis, it forms (B), (C), and a diatomic gas (D). If (A) is indeed XeF2, hydrolysis would yield xenon (B), hydrofluoric acid (C), and oxygen (D).

4. **Identifying Diatomic Gas (D)**:
- The diatomic gas (D) produced during hydrolysis is likely to be oxygen (O2).

5. **Formation of Pale Blue Gas (E)**:
- When pure and dry (D) is subjected to silent electric discharge, it produces another pale blue gas (E). This gas is likely ozone (O3), which is known for its pale blue color and strong oxidizing properties.

6. **Dissolution of (E)**:
- The pale blue gas (E) dissolves in potassium hydroxide to form an orange-colored solid that is paramagnetic. This solid is likely potassium ozonide (KO3), which is known to exhibit paramagnetism.

7. **Addition Compounds**:
- (A) reacts with IF5, SbF5, PF5, etc., to form addition compounds. This is consistent with xenon compounds, which can form various addition complexes.

8. **Electrolysis of (C)**:
- The highly associated liquid (C) forms an addition compound (F) with KF, and upon electrolysis in molten state, it produces a highly reactive gas (G). This gas is likely fluorine (F2).

9. **Formation of (A)**:
- When (B) and (G) are taken in a 2:1 ratio and heated in a nickel tube at 400°C and 6 atm pressure, they can reform (A), which is consistent with the reaction of xenon and fluorine.

10. **Ionization Energy Comparison**:
- The first ionization energy (IE1) of (B) (xenon) is fairly close to (D) (oxygen), which is consistent with the known ionization energies of these elements.

**Conclusion**:
- Therefore, we can conclude that:
- (D) is oxygen (O2)
- (E) is ozone (O3)