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Fifth group elements form hydrides to ty...

Fifth group elements form hydrides to type `AH_(3)`. The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides .
The boiling points of the hydrides of V-group elements are in the
order :

A

`NH_3 gt PH_3 gt AsH_3 gt SbH_3`

B

`NH_3 gt AsH_3 gt SbH_3 gt PH_3 `

C

`SbH_3 gt NH_3 gt AsH_3 gt PH_3 `

D

`AsH_3 gt SbH_3 gt NH_3 gt PH_3 `

Text Solution

Verified by Experts

The correct Answer is:
C

Due to increase in size from `PH_3` to `SbH_3` the van der Waals forces increase.So their boiling points increase from `PH_3` to `SbH_3`.But does to intermolecular hydrogen bonding, `NH_3` has very high boiling point but less than that of `SbH_3`.
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Fifth group elements form hydrides to type AH_(3) . The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides . Reducing power of V-group hydrides are in order :

Fifth group elements form hydrides to type AH_(3) . The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides . The H-M-H bond angle of V group hydrides decrease from 107^(circ) to 90^(circ) for NH_(3) to SbH_(3) , this is due to:

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