Lithium aluminium hydride reacts with silicon tetrachloride to form

Explanation

To solve the question regarding the reaction between Lithium Aluminium Hydride (LiAlH4) and Silicon Tetrachloride (SiCl4), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are Lithium Aluminium Hydride (LiAlH4) and Silicon Tetrachloride (SiCl4).

2. **Write the Chemical Reaction**:
- When LiAlH4 reacts with SiCl4, the reaction can be represented as:
\[ \text{LiAlH}_4 + \text{SiCl}_4 \rightarrow \text{LiCl} + \text{AlCl}_3 + \text{SiH}_4 \]

3. **Identify the Products**:
- From the reaction, we can see that the products formed are:
- Lithium Chloride (LiCl)
- Aluminium Chloride (AlCl3)
- Silicon Hydride (SiH4)

4. **Check for Balancing**:
- The equation is already balanced as it maintains the same number of each type of atom on both sides of the equation.

5. **Final Answer**:
- Therefore, the products formed from the reaction of Lithium Aluminium Hydride with Silicon Tetrachloride are:
- Lithium Chloride (LiCl)
- Aluminium Chloride (AlCl3)
- Silicon Hydride (SiH4)